An illustration. Suppose that array contains three integers, 0, 1, 2, and that i is equal to 1. array[i]++ changes array[1] to 2, evaluates to 1 and leaves i equal to 1. array[i++] does not modify array, evaluates to 1 and changes i to 2. A suffix operators, which you are using here, evaluates to the value of the expression before it is ...
Array increment positioning with respect to indexer in C - array [i ...
The third way of initializing is useful when you declare an array first and then initialize it, pass an array as a function argument, or return an array. The explicit type is required.
How do I declare and initialize an array in Java? - Stack Overflow
We'll use that fact later. Array.apply(null, [undefined, undefined, undefined]) is equivalent to Array(undefined, undefined, undefined), which produces a three-element array and assigns undefined to each element. How can you generalize that to N elements? Consider how Array() works, which goes something like this:
When creating a 2D array, how does one remember whether rows or columns are specified first?
Which comes first in a 2D array, rows or columns? - Stack Overflow
There are plenty of applications for both approaches; it just depends on what you're using the array for. If you iterate over an array with for.. of, the body of the loop is executed length times, and the loop control variable is set to undefined for any items not actually present in the array.
How does index of ^1 returns the last item in an array? What does ^1 mean in C# compiler? Does it have performance benefit vs numbers[numbers.Count()-1]?