calculus - Evaluate an integral involving a series and product in the ...
Revise how to find the area above and below the x axis and the area between two curves by integrating, then evaluating from the limits of integration. Higher Maths - Applying integral calculus.
jagranjosh.com: Integral Calculus: Quick Revision of Formulae for IIT JEE, UPSEE & WBJEE
Get important formulae from unit Integral Calculus for quick revision. These formulae are very useful during competitive examination. This revision notes includes chapters – Indefinite Integral, ...
Integral Calculus: Quick Revision of Formulae for IIT JEE, UPSEE & WBJEE
THIS book seems well adapted to serve as a text-book for a first course in the differential and integral calculus. Fourteen chapters deal with the differential calculus and its applications to maxima ...
The integral which you describe has no closed form which is to say that it cannot be expressed in elementary functions. For example, you can express $\int x^2 \mathrm {d}x$ in elementary functions such as $\frac {x^3} {3} +C$. However, the indefinite integral from $ (-\infty,\infty)$ does exist and it is $\sqrt {\pi}$ so explicitly: $$\int^ {\infty}_ {-\infty} e^ {-x^2} = \sqrt {\pi}$$ Note ...
A different type of integral, if you want to call it an integral, is a "path integral". These are actually defined by a "normal" integral (such as a Riemann integral), but path integrals do not seek to find the area under a curve. I think of them as finding a weighted, total displacement along a curve.