In 1977, ABBA released a song that would mark a turning point in their career. Their single, "Knowing Me, Knowing You" became a global success, reaching No. 1 on charts in multiple countries, ...
LONDON — Is it possible to have too much ABBA? Knowing me, knowing you, the answer is no. The spangly Swedish quartet that gave the world “Waterloo” and “Dancing Queen” has sold 400 million records ...
Is it possible to have too much ABBA? Knowing me, knowing you, the answer is no. The spangly Swedish quartet that gave the world “Waterloo” and “Dancing Queen” has sold 400 million records since its ...
That is, there seems to be fairly strong symbolic evidence that for $n=4$, if $ABBA-BAAB = A-B$ and $A$ is nilpotent, then $B^4 = \lambda I$ for some $\lambda$.
Because abab is the same as aabb. I was how to solve these problems with the blank slot method, i.e. _ _ _ _. If I do this manually, it's clear to me the answer is 6, aabb abab abba baba bbaa baab Which is the same as $$\binom {4} {2}$$ But I don't really understand why this is true? How is this supposed to be done without brute forcing the ...
Although both belong to a much broad combination of N=2 and n=4 (AAAA, ABBA, BBBB...), where order matters and repetition is allowed, both can be rearranged in different ways: First one: AABB, BBAA,
For example a palindrome of length $4$ is always divisible by $11$ because palindromes of length $4$ are in the form of: $$\overline{abba}$$ so it is equal to $$1001a+110b$$ and $1001$ and $110$ are